20x^2+164x-144=0

Solution for 20x^2+164x-144=0 equation:

20x^2+164x-144=0

a = 20; b = 164; c = -144;
Δ = b2-4ac
Δ = 1642-4·20·(-144)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(164)-196}{2*20}=\frac{-360}{40}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(164)+196}{2*20}=\frac{32}{40}
=4/5
$